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If the number of terms in the expansion of (1-2/x+4/(x^2))^n , x!=0, is 28, then the sum of the coefficients of all the terms in this expansion, is : (1) 64 (2) 2187 (3) 243 (4) 729
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A sequence is defined by an = n^3 - 6n^2 + 11n - 6, n∈ N . Show that the first three terms of the sequence are zero and all other terms are positive.